Bonsoir, Pouvez vous m'aidez pour ce dm Svp.

bonsoir,

exo 1 :

1) 4(1-2x)²-1 =
4(1-4x+4x²)-1 =
4-16x+16x²-1 =
16x²-16x+3

2) [2(1-2x)-1][2(1-2x)+1] =
(2-4x-1)(2-4x+1) =
(-4x+1)(-4x+3)

3) f(x) = -1
4(1-2x)²-1 = -1
4(1-2x)²-1+1  = 0
4(1-2x)² = 0
1-2x =0
-2x =-1
x =1/2

f(x) = 0
(-4x+1)(-4x+3) =0
-4x+1  =0
-4x =-1
x = 1/4
-4x=3 = 0
-4x = -3
x =3/4

f(x) = 3
16x²-16x+3 = 3
16x²-16x+3-3 =0
16x²-16x = 0
16x(x-1) = 0
x-1  =0
x = 1
16x =0
x = 0

exo 2 :

un autre message